3.2370 \(\int \frac{(1-2 x)^{3/2}}{(2+3 x)^6 \sqrt{3+5 x}} \, dx\)

Optimal. Leaf size=180 \[ \frac{87374783 \sqrt{1-2 x} \sqrt{5 x+3}}{131712 (3 x+2)}+\frac{835409 \sqrt{1-2 x} \sqrt{5 x+3}}{9408 (3 x+2)^2}+\frac{23909 \sqrt{1-2 x} \sqrt{5 x+3}}{1680 (3 x+2)^3}+\frac{293 \sqrt{1-2 x} \sqrt{5 x+3}}{120 (3 x+2)^4}+\frac{7 \sqrt{1-2 x} \sqrt{5 x+3}}{15 (3 x+2)^5}-\frac{333216939 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{43904 \sqrt{7}} \]

[Out]

(7*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(15*(2 + 3*x)^5) + (293*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(120*(2 + 3*x)^4) + (2390
9*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(1680*(2 + 3*x)^3) + (835409*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(9408*(2 + 3*x)^2) +
(87374783*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(131712*(2 + 3*x)) - (333216939*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 +
5*x])])/(43904*Sqrt[7])

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Rubi [A]  time = 0.06689, antiderivative size = 180, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {98, 151, 12, 93, 204} \[ \frac{87374783 \sqrt{1-2 x} \sqrt{5 x+3}}{131712 (3 x+2)}+\frac{835409 \sqrt{1-2 x} \sqrt{5 x+3}}{9408 (3 x+2)^2}+\frac{23909 \sqrt{1-2 x} \sqrt{5 x+3}}{1680 (3 x+2)^3}+\frac{293 \sqrt{1-2 x} \sqrt{5 x+3}}{120 (3 x+2)^4}+\frac{7 \sqrt{1-2 x} \sqrt{5 x+3}}{15 (3 x+2)^5}-\frac{333216939 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{43904 \sqrt{7}} \]

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^(3/2)/((2 + 3*x)^6*Sqrt[3 + 5*x]),x]

[Out]

(7*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(15*(2 + 3*x)^5) + (293*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(120*(2 + 3*x)^4) + (2390
9*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(1680*(2 + 3*x)^3) + (835409*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(9408*(2 + 3*x)^2) +
(87374783*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/(131712*(2 + 3*x)) - (333216939*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 +
5*x])])/(43904*Sqrt[7])

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
 a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
 FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 151

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*
f)), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegerQ[m]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 93

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{(1-2 x)^{3/2}}{(2+3 x)^6 \sqrt{3+5 x}} \, dx &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{1}{15} \int \frac{\frac{337}{2}-260 x}{\sqrt{1-2 x} (2+3 x)^5 \sqrt{3+5 x}} \, dx\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{1}{420} \int \frac{\frac{85323}{4}-30765 x}{\sqrt{1-2 x} (2+3 x)^4 \sqrt{3+5 x}} \, dx\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{\int \frac{\frac{15850275}{8}-2510445 x}{\sqrt{1-2 x} (2+3 x)^3 \sqrt{3+5 x}} \, dx}{8820}\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{835409 \sqrt{1-2 x} \sqrt{3+5 x}}{9408 (2+3 x)^2}+\frac{\int \frac{\frac{1888544805}{16}-\frac{438589725 x}{4}}{\sqrt{1-2 x} (2+3 x)^2 \sqrt{3+5 x}} \, dx}{123480}\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{835409 \sqrt{1-2 x} \sqrt{3+5 x}}{9408 (2+3 x)^2}+\frac{87374783 \sqrt{1-2 x} \sqrt{3+5 x}}{131712 (2+3 x)}+\frac{\int \frac{104963335785}{32 \sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx}{864360}\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{835409 \sqrt{1-2 x} \sqrt{3+5 x}}{9408 (2+3 x)^2}+\frac{87374783 \sqrt{1-2 x} \sqrt{3+5 x}}{131712 (2+3 x)}+\frac{333216939 \int \frac{1}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx}{87808}\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{835409 \sqrt{1-2 x} \sqrt{3+5 x}}{9408 (2+3 x)^2}+\frac{87374783 \sqrt{1-2 x} \sqrt{3+5 x}}{131712 (2+3 x)}+\frac{333216939 \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,\frac{\sqrt{1-2 x}}{\sqrt{3+5 x}}\right )}{43904}\\ &=\frac{7 \sqrt{1-2 x} \sqrt{3+5 x}}{15 (2+3 x)^5}+\frac{293 \sqrt{1-2 x} \sqrt{3+5 x}}{120 (2+3 x)^4}+\frac{23909 \sqrt{1-2 x} \sqrt{3+5 x}}{1680 (2+3 x)^3}+\frac{835409 \sqrt{1-2 x} \sqrt{3+5 x}}{9408 (2+3 x)^2}+\frac{87374783 \sqrt{1-2 x} \sqrt{3+5 x}}{131712 (2+3 x)}-\frac{333216939 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{3+5 x}}\right )}{43904 \sqrt{7}}\\ \end{align*}

Mathematica [A]  time = 0.129285, size = 135, normalized size = 0.75 \[ \frac{1}{35} \left (\frac{5 \left (\frac{7 \sqrt{1-2 x} \sqrt{5 x+3} \left (262124349 x^2+361165738 x+124968544\right )}{(3 x+2)^3}-333216939 \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )\right )}{43904}+\frac{975 \sqrt{5 x+3} (1-2 x)^{5/2}}{56 (3 x+2)^4}+\frac{3 \sqrt{5 x+3} (1-2 x)^{5/2}}{(3 x+2)^5}\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^(3/2)/((2 + 3*x)^6*Sqrt[3 + 5*x]),x]

[Out]

((3*(1 - 2*x)^(5/2)*Sqrt[3 + 5*x])/(2 + 3*x)^5 + (975*(1 - 2*x)^(5/2)*Sqrt[3 + 5*x])/(56*(2 + 3*x)^4) + (5*((7
*Sqrt[1 - 2*x]*Sqrt[3 + 5*x]*(124968544 + 361165738*x + 262124349*x^2))/(2 + 3*x)^3 - 333216939*Sqrt[7]*ArcTan
[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])]))/43904)/35

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Maple [B]  time = 0.012, size = 298, normalized size = 1.7 \begin{align*}{\frac{1}{3073280\, \left ( 2+3\,x \right ) ^{5}}\sqrt{1-2\,x}\sqrt{3+5\,x} \left ( 404858580885\,\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) \sqrt{7}{x}^{5}+1349528602950\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{4}+1799371470600\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{3}+165138339870\,{x}^{4}\sqrt{-10\,{x}^{2}-x+3}+1199580980400\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{2}+447737213700\,{x}^{3}\sqrt{-10\,{x}^{2}-x+3}+399860326800\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) x+455499158856\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}+53314710240\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) +206091285904\,x\sqrt{-10\,{x}^{2}-x+3}+34994513344\,\sqrt{-10\,{x}^{2}-x+3} \right ){\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^(3/2)/(2+3*x)^6/(3+5*x)^(1/2),x)

[Out]

1/3073280*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(404858580885*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*7^(1/2)
*x^5+1349528602950*7^(1/2)*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^4+1799371470600*7^(1/2)*arctan
(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^3+165138339870*x^4*(-10*x^2-x+3)^(1/2)+1199580980400*7^(1/2)*ar
ctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x^2+447737213700*x^3*(-10*x^2-x+3)^(1/2)+399860326800*7^(1/2)
*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))*x+455499158856*x^2*(-10*x^2-x+3)^(1/2)+53314710240*7^(1/2)
*arctan(1/14*(37*x+20)*7^(1/2)/(-10*x^2-x+3)^(1/2))+206091285904*x*(-10*x^2-x+3)^(1/2)+34994513344*(-10*x^2-x+
3)^(1/2))/(-10*x^2-x+3)^(1/2)/(2+3*x)^5

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Maxima [A]  time = 2.72956, size = 248, normalized size = 1.38 \begin{align*} \frac{333216939}{614656} \, \sqrt{7} \arcsin \left (\frac{37 \, x}{11 \,{\left | 3 \, x + 2 \right |}} + \frac{20}{11 \,{\left | 3 \, x + 2 \right |}}\right ) + \frac{7 \, \sqrt{-10 \, x^{2} - x + 3}}{15 \,{\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} + \frac{293 \, \sqrt{-10 \, x^{2} - x + 3}}{120 \,{\left (81 \, x^{4} + 216 \, x^{3} + 216 \, x^{2} + 96 \, x + 16\right )}} + \frac{23909 \, \sqrt{-10 \, x^{2} - x + 3}}{1680 \,{\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} + \frac{835409 \, \sqrt{-10 \, x^{2} - x + 3}}{9408 \,{\left (9 \, x^{2} + 12 \, x + 4\right )}} + \frac{87374783 \, \sqrt{-10 \, x^{2} - x + 3}}{131712 \,{\left (3 \, x + 2\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)/(2+3*x)^6/(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

333216939/614656*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) + 7/15*sqrt(-10*x^2 - x + 3)/(243*x
^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32) + 293/120*sqrt(-10*x^2 - x + 3)/(81*x^4 + 216*x^3 + 216*x^2 +
96*x + 16) + 23909/1680*sqrt(-10*x^2 - x + 3)/(27*x^3 + 54*x^2 + 36*x + 8) + 835409/9408*sqrt(-10*x^2 - x + 3)
/(9*x^2 + 12*x + 4) + 87374783/131712*sqrt(-10*x^2 - x + 3)/(3*x + 2)

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Fricas [A]  time = 1.58555, size = 455, normalized size = 2.53 \begin{align*} -\frac{1666084695 \, \sqrt{7}{\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )} \arctan \left (\frac{\sqrt{7}{\left (37 \, x + 20\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{14 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \,{\left (11795595705 \, x^{4} + 31981229550 \, x^{3} + 32535654204 \, x^{2} + 14720806136 \, x + 2499608096\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{3073280 \,{\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)/(2+3*x)^6/(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

-1/3073280*(1666084695*sqrt(7)*(243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32)*arctan(1/14*sqrt(7)*(37*x
 + 20)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3)) - 14*(11795595705*x^4 + 31981229550*x^3 + 32535654204*x^
2 + 14720806136*x + 2499608096)*sqrt(5*x + 3)*sqrt(-2*x + 1))/(243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x
+ 32)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(3/2)/(2+3*x)**6/(3+5*x)**(1/2),x)

[Out]

Timed out

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Giac [B]  time = 3.53892, size = 594, normalized size = 3.3 \begin{align*} \frac{333216939}{6146560} \, \sqrt{70} \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{70} \sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} + \frac{121 \,{\left (8222141 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{9} + 5797080240 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{7} + 1842336276480 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{5} + 282112659584000 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{3} + 16926759575040000 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}\right )}}{21952 \,{\left ({\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{2} + 280\right )}^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(3/2)/(2+3*x)^6/(3+5*x)^(1/2),x, algorithm="giac")

[Out]

333216939/6146560*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - s
qrt(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) + 121/21952*(8222141*sqrt(10)*((sqrt(2)*sqrt(
-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^9 + 5797080240*sq
rt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(2
2)))^7 + 1842336276480*sqrt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)
*sqrt(-10*x + 5) - sqrt(22)))^5 + 282112659584000*sqrt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3)
 - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^3 + 16926759575040000*sqrt(10)*((sqrt(2)*sqrt(-10*x +
 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))))/(((sqrt(2)*sqrt(-10*x +
 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^2 + 280)^5